find the value of k if one of the root of k x square - 7 x + 12 is equal to zero x 3
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Since one of the root is 3,,, then if we put x=3 in the given equation, it will be equal to 0.
So putting x=3 in the given equation, we get:
K*3*3-7*3+12=0
9k-21+12=0
9k=21-12
9k= 9
K=9/9
K=1
Therefore, the answer is k=1.
So putting x=3 in the given equation, we get:
K*3*3-7*3+12=0
9k-21+12=0
9k=21-12
9k= 9
K=9/9
K=1
Therefore, the answer is k=1.
atharvadamakale88:
thanks
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