Question

find the value of k if one of the root of quadratic equation 5x²-kx-6=0 is 6​

Answer 1

Answer:

Analysis→

Here we're given a quadratic equation 5x²-kx-6=0 and one of its zeroes(roots) is 6. And we've to find the value of k(coefficient of x). And if the root is given, so we can directly put it in place of x, and can get our answer.

Given→

• Equation= 5x²-kx-6
• Root= 6

To Find→

The value of k in the given equation.

Answer→

$\rm\rightarrow{5x^2-kx-6=0}$

$\rm\rightarrow{5(6)^2-k(6)-6=0}$

$\rm\rightarrow{5(36)-6k-6=0}$

$\rm\rightarrow{180-6k-6=0}$

$\rm\rightarrow{174-6k=0}$

$\rm\rightarrow{-6k=-174}$

$\rm\rightarrow{k=\dfrac{-174}{-6}}$

$\rm\rightarrow{k=\dfrac{\cancel{-174}}{\cancel{-6}}}$

$\rm\rightarrow{k=29}$

${\boxed{\boxed{\rightarrow{\rm{k=29\checkmark}}}}}$

☞ Hence the value of k(coefficient of x) in the given equation is 29 which is the required answer.

HOPE IT HELPS.