Question

Find the value of k, if one of the roots of the quadratic equation
(ii) kx2-11x+12=0 is4.​

Answer 1

Given,

One of the roots of the quadratic equation kx²-11x+12 = 0 is 4.

To Find,

The value of k.

Solution,

Since one of the roots of the quadratic equation is 4

So, this value will satisfy the given quadratic equation.

Now,

k(4)²-11(4)+12 = 0

Solving this equation,

16k-44+12 = 0

16k = 32

k = 2

Hence, the value of k is 2.

Answer 2

Answer:

The value of k is

Step-by-step explanation:

Given:

$kx^{2} -11x+12=0\\x=4$

To find:

The value of k.

Solution:

$kx^{2} -11x+12=0\\x=4\\k(4^{2}) -11(4)+12=0\\k(16)-44+12=0\\16k-32=0\\16k=32\\k=\frac{32}{16} \\k=2$

Hence, the value of k is 2.