Math, asked by Samte, 1 year ago

find the value of k if one of the zero of quadratic polynomial is x2+kx+15 is 3​

Answers

Answered by mdatifnasim70mp64jpe
0

Answer:

hi friend,

given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3

so when we substitute -3 in the polynomial ,we get 0

→(k-1)(-3)²+k(-3)+1=0

→9k-9-3k+1=0

→6k-8=0

→k=8/6=4/3

I hope this will help u ;)

Answered by Anonymous
0

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8. ....

 \large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }

Hence, the value of ‘k’ is founded .

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