Find the value of k if one of the zeroes of the quadratic polynomial
(k-1)x2 + k x + 1 is -3.
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Answer:
Step-by-step explanation:
since -3 is zerof of given polynomial p(x).
so, p(-3)=0
⇒(k-1)x²+ k x + 1 =0
⇒(k-1)×(-3)²+k×-3+1=0
⇒9k-9-3k+1=0
⇒6k=8
⇒k=4/3.
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