Question

Find the value of k if one zero of the quadratic equation is 2. 2x² - 3 + k = 0.​

Answer 1

We have,

We have,2x 2 −3x+k=0

We have,2x 2 −3x+k=0and one zero is reciprocal to the other.

We have,2x 2 −3x+k=0and one zero is reciprocal to the other.Let one zero =x then other zero = x1

We have,2x 2 −3x+k=0and one zero is reciprocal to the other.Let one zero =x then other zero = x1We know that,

x× x1 = cofficentofx 2 cconstantter 1= 2k k=2

Hence, this is the answer.

Answer 2

Question:-

Find the value of k if one zero of the quadratic equation is 2. 2x² - 3x + k = 0.

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Given:-

• Quadratic Equation = 2x² - 3x + k = 0.
• Zero of the Quadratic Equation is 2.

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To find:-

• Value of k.

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Solution:-

• Putting x = 2

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$\large{\tt{\longmapsto{2(2)^2 - 3(2) + k = 0}}}$

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$\large{\tt{\longmapsto{2(4) - 6 + k = 0}}}$

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$\large{\tt{\longmapsto{8 - 6 + k = 0}}}$

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$\large{\tt{\longmapsto{2 + k = 0}}}$

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$\boxed{\large{\tt{\longmapsto{\red{k = -2}}}}}$

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Therefore, the value of k is-2.

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