Question

find the value of k if points P (- 5, 1) Q(1,k) R(4,-2)are in collinear also find the length of PQ QR and PR​

Answer 1

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Answer 2

$x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) \\ \\ | - 5(k - - 2) + 1( - 2 - 1) + 4(1 - k)| = 0 \\ \\ - 5k + 10 - 3 + 4 - 4k = 0 \\ \\ - 7k = - 11 \\ \\ k = \frac{11}{7}$
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