Question

find the value of K, if slope of line passing through P(K,3) and Q (1,2) is -1/3

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

K = -2

Step-by-step explanation:

We know,

$Slope = \frac{(y_{2} - y_{1})}{(x_{2} - x_{1})}$

Thus,

Slope = $\frac{3-2}{K-1} \\= \frac{1}{K-1}$

This is equal to -1/3

$\frac{1}{K-1} = \frac{-1}{3} \\=> -K + 1 = 3\\=> K = -2$