find the value of k if t+1 is a factor of 2t2 +kt-1
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Answered by
6
2t^2 + kt - 1
t+1=0
t= -1
as putting t = -1 in the equation
2×(-1)^2 +k×(-1 ) - 1 = 0
2 - k - 1 =0
- k = -1
k =1
pls mark as brainliest answer
t+1=0
t= -1
as putting t = -1 in the equation
2×(-1)^2 +k×(-1 ) - 1 = 0
2 - k - 1 =0
- k = -1
k =1
pls mark as brainliest answer
Answered by
1
t+1=0
t=(-1)
2t^2+kt -1 =0
2(-1) ^2+k(-1) -1=0
2 (1) -k -1=0
2-k-1=0
1-k=0
-k= -1
k=1
t=(-1)
2t^2+kt -1 =0
2(-1) ^2+k(-1) -1=0
2 (1) -k -1=0
2-k-1=0
1-k=0
-k= -1
k=1
shubhdha:
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