Question

Find the value of k, if the area
of a quadrilateral is 28 sq units
whose vertices are (-4,-2) (3,k)
(3,-2) (2,3):​


plz....... solve it

Answer 1

Given:

The area of a quadrilateral is 28 sq units whose vertices are (-4,-2) (3,k) (3,-2) (2,3):​  

To find:

Find the value of k

Solution:

From given, we have,

The area of a quadrilateral is 28 sq units whose vertices are (-4,-2) (3,k) (3,-2) (2,3)

we use the formula,

Area of quadrilateral = 1/2 { (x1y2 + x2y3 + x3y4 + x4y1) - (x2y1 + x3y2 + x4y3 + x1y4)}

28 = 1/2  { [(-4 × k) + (3 × -2) + (3 × 3) + (2 × -2)] - [(3 × -2) + (3 × k) + (2 × -2) + (-4 × 3) ]}

upon solving, we get,

56 = -4k - 6 + 9 - 4 + 6 - 3k + 4 + 12

56 = -7k + 21

56 - 21 = -7k

35 = -7k

k = -5

Therefore, the value of k is -5.

Answer 2

Step-by-step explanation:

thank you qqyello w for your correct answer