Question

Find the value of k, if the area of a quadrilateral is 28 sq.units, whose vertices are (–4, –2),

(–3, k), (3, –2) and (2, 3).​

Answer 1

Answer:

the value of k is -5

Step-by-step explanation:

Area of quadrilateral = 28 square units

[(-4k + 6 + 9 - 4) - (6 + 3k - 4 - 12)] = 28(2)

(-4k + 11) - (3k - 10) = 56

-4k + 11 - 3k + 10 = 56

-7k = 56-21

-7k = 35

k = 35/(-7)

k = -5

Hence the value of k is -5.