Math, asked by harikrishnacs409, 11 months ago

find the value of k,if the area of the quadrilateral is 28 units whose vertices are (-4,-2),(-3,k),(3,-2)&(2,3)​

Answers

Answered by mohan4197
5

Step-by-step explanation:

-4 -2

-3 K

3 -2

2 3

by cross method

28= 1/2 ×(-4k+6+9+4-3k-6)

28 ×2=-7k+13

56-13=-7k

43=-7k

-43/7=k

this is the answer

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