Question

Find the value of K , If the area of the Quadrilateral is 35 sq. units. Whose vertices are (-9,-2),(-8,K),(2,2) and (1,-3).


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Answer 1

Answer:

Step-by-step explanation:

Area of triangle is △=  

2

​35(given)△=(20−4k)−(8+6k)+(8+30)=70[opening from C  

3

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]50−10k=70k=−2

taking +ve sign

⇒−10k+50=70

⇒−10k=70−50

⇒−10k=20

⇒k=−2

taking −ve sign

⇒−10k+50=−70

⇒−10k=−70−50

⇒−10k=−120

⇒k=12

⇒k=−2,12

Answer 2

Answer:

35(given)△=(20−4k)−(8+6k)+(8+30)=70[opening from C

3

]50−10k=70k=−2

taking +ve sign

⇒−10k+50=70

⇒−10k=70−50

⇒−10k=20

⇒k=−2

taking −ve sign

⇒−10k+50=−70

⇒−10k=−70−50

⇒−10k=−120

⇒k=12

⇒k=−2,12