Question

Find the value of 'k'. If the co-ordinates of the points A(2,-2), B(-4, 2) and
C(-7, k) are collinear. with formula​

Answer 1

Answer:

k=12

Step-by-step explanation:

do determinant=0 get value of k

Answer 2

$\tt\: as \: we \: know \\ \tt{ \red{ar \: of \: triangle}} ={ \orange { \frac{1}{2}(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))}} \\ \\ \tt \: 0= \frac{1}{2} (2(2-k)+(-4)(k+2)+(-7)(-2-2)) \\ \\ \tt \ \:0=1/2(4-2k-4k-8+28) \\ \\ \tt \: 0=1/2(-6k+24) \\ \\ \tt \ \: 0=-3k+12 \\ \\ \tt \: 3k=12 \\ \\ \tt \: k=12/3 \\ \\ \tt \: k=4$

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