find the value of k if the distance between the points A(-3 , -4) And B (k, -5) is 9 units
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So, as given that the points are collinear, then, x1(y2−y3)+x2(y3−y1)+x3(y1−y2)=0. k(−2−4)+6(4−3)+3(3+2)=0. k(−6)+6(1)+(−3)×5=0. −6k+6−15=0. −6k−9=0.
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