Question

Find the value of k if the division of k x^2+9x^2+4x-10by x+3 leaves a remainder -22

Answer 1

Answer:

The value of k is when x+3 is divided and the remainder is -22 is -69/9

Step-by-step explanation:

kx²+9x²+4x-10/x+3

x+3=0

x=-3

k[-3]²+9×[-3]²+4[-3]-10=0

k[9]+9×[9]-12-10=0

9k+81-22=0

9k+59=0

9k=-59

k=-59/9