Question

find the value of k if the division of kx^3+9x^2+4x-10 by x+3 leaves a remainder -22

its urgent​

Answer 1

Answer:

f(-3)= kx^3+9x^2+4x-10 = -22

Step-by-step explanation:

k(-3)^2 + 9(-3)^2 +4(-3) - 10 = -22

k(9) + 9(9) -12 -10 = -22

9k + 81 -22 + 22 = 0

9k = -81

k = -81/9

k = -9