Find the value of k if the division of kx cube plus 9x square plus 4x minus 10 by x plus 3 leaves a remainder -22
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If you are dividing by x+3 then take x+3=0 or x=-3
put this value of x in the polynomial
k(-3)^3 + 9(-3)^2 +4(-3) -10 = -22
-27k + 81 -12-10=-22
-27k = -81
k=81/27=3 Ans
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