Question

find the value of K if the division of kx³+9x²+4x-10 by x+3 leaves a remainder -22.​

Answer 1

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Answer 2

Step-by-step explanation:

X+3=0

x= -4

k(-3)cube+9(-3)square+4(-3)-10

-27-81-12-10=k

-55-22=k

-77

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