find the value of k if the division of kx³+9x²+4x-10 by x-3 leaves a remainder -22
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3
Given:
In the division of kx³ + 9x² +4x -10 by x +3 leaves a remainder -22.
To find:
The value of k
Solution:
Here we have given that the division of kx³ + 9x² +4x -10 by x +3 leaves a remainder -22.
so on putting the value of x as -3 we should get the remainder as -22
Putting the value of the x as -3 we get the value as:
kx³ + 9x² +4x -10 = -22
k(-3)³ + 9(-3)² +4(-3) -10 = -22
-27k +81 -12 - 10 = -22
27k = 81
k = 81/27
k = 3
Hence, The value of k is 3
Answered by
1
Answer:
same as kritikaas12
Step-by-step explanation:
same as kritikaas12
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