Question

Find the value of k if the equation 3kx^2 – 4 ( kx – 1 ) = 0 has equal

real roots​

Answer 1

Answer:

k=3

Step-by-step explanation:

3kx^2-4(kx-1)=0

=3kx^2-4kx+4=0

compare the given equation with ax^2+bx+c=0 we get, a=3k, b=4k,c=4

since, the roots are real and equal

The discriminant = 0

b^2-4ac=0

(4k) ^2-4*3k*4=0

16k^2-48k=0

16k(k-3)=0

k-3=0

k=3

The value of the k is 3