Question

Find the value of k if the equation 3x^2-4x+k=0 has rare roots

Answer 1

Answer:

k =1

Step-by-step explanation:

Let us take x=1

3(1)^2 - 4(1) + k = 0

4 - 3 + k =0

-1 + k= 0

when -1 goes to the right hand side

k = 0+1

k= 1