Question

find the value of k if the equations 2x+4y+7=0 and 10x+20y+k=0are coincident ​

Answer 1

Step-by-step explanation:

d=[2 4 ] =40-40=0

10 20

dx= 4 7 =4k-140=140/4=35

20 k

Answer 2

Answer:

k=35

Step-by-step explanation:

It is given that.. these two equations are coincident..

As per the condition of coincident of linear equation; a1/a2 = b1/b2 = c1/c2; here, a1=2, b1=4, c1=7; a2=10, b2=20, c2=k

As per the given condition...

2/10= 4/20= 7/k

By cancelling, we get

1/5= 1/5= 7/k

1/5= 7/k

By transposing, we get

k= 7*5

k= 35

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