Question

find the value of k,if the following are consecutive terms of AP 2,k,26​

Answer 1

Answer:k = 14

Step-by-step explanation:

t1 = 2

a = 2 (1)

t3=26

a + 2d =26 (2)

from (1) & (2),

2d =24

d = 12

k = a + d

=2 + 12

=14

Answer 2

The value of k = 14

Given :

2 , k , 26 are consecutive terms of an AP

To find :

The value of k

Solution :

Step 1 of 2 :

Form the equation

We know that , if three terms a , b , c are in AP then

2b = a + c

Here it is given that 2 , k , 26 are consecutive terms of an AP

∴ 2 × k = 2 + 26

Step 2 of 2 :

Find the value of k

2 × k = 2 + 26

⇒ 2k = 28

⇒ k = 28/2

⇒ k = 14

Hence the required value of k = 14

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