Question

Find the value of k if the following quadratic equation has two equal (real) roots:
(k+4)x²+(k+1)x+1=0​

Answer 1

K+4x2+(k+1)x+1= 0.52

Answer 2

HERE IS YOUR ANSWER MATE.....;

IF ROOTS ARE EQUAL THEN B^2-4AC = 0

$= > (k + 1) {}^{2} - 4 \times (k + 4) \times 1 = 0$

$= > k {}^{2} + 1 + 2k - 4k - 16 = 0$

$= > k {}^{2} - 2k - 15 = 0$

$= > k {}^{2} + 3k- 5k - 15 = 0$

$= > k(k + 3) - 5(k + 3) = 0$

$= > (k - 5)(k + 3) = 0$

$k = 5$

$k = - 3$

HOPE ITS HELPFUL....:-)