Find the value of k if the given equation has no solution 3x - 4y + 7 is equal to zero
Kx + 3y - 5 is equal to zero
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0
Answer:
Step-by-step explanation:
Fir a pair of Linear equation to have no solution
a1/a2 = b1/b2 not equal to c1/c2
Here a1=3, b1=-4, c1=7
a2 =k, b2 =3, c2= -5
a1/a2 = b1/b2 => 3/k = -4/3
-4k = 9
k = -4/9
b1/b2 not equal to c1/c2
3/k not equal to 7/-5
7k not equal to -15
k not equal to -15/7
Hence k = -4/9 and k not equal to -15/7
Answered by
0
Answer:
3x-4y+7=0
kx+3y-5=0
kx=-3y+5
k=-3y+5/x
x=-3y+5/k
put this value in eq -1
3(-3y+5/k)-4y+7=0
-9y+15/k-4y+7=0
-9y+15-4yk+7k=0
-9y-4yk+7k=-15
-y(9+4k)+7k=-15
9+4k+7k=15/y
[11k=15/y-9]
[k=15/yk-9]
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