Question

find the value of k if the given pair of linear equations has no solutions
kx-2y=0
6x-2y-3=0​

Answer 1

Answer:

Step-by-step explanation:

The given system is

Kx - y - 2 =0

6x - 2y -3 = 0

Here a₁ = k, b₁ =-1, c₁ =-2,a₂ = 6, b₂ = -2,c= -3

For the system to have a unique solution we must have

a₁/a₂ ≠ b₁/b₂

k /6  ≠ -1 /-2

-2k  ≠ -6

k  ≠ 3

Hence K  ≠ 3

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Step-by-step explanation: