Question

Find the value of k if the given quadratic equation is a real seed 5X2- 2KX + 20​

Answer 1

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Quadratic equation:-

5x²−2kx+20=0

It is given that the roots of the quadratic equation are real and equal, Then discriminant D=0.

Comparing the given equation with ax2+bx+c=0

we have a=5,b=−2k and c=20

Now, D = 0

∴b² − 4ac=0

∴(−2k)²−4(5)(20)=0

∴4k²−400=0

∴k² = 100

∴k = +10

Thus, 

k = 10 or −10.