find the value of k if the line joining P(2,3) and Q(5,7) is perpendicular to the line joining A(5,k) and B(3,2)
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Answer:
√(5-2)²+(7-3)²=√(3-5)²+(2-k)²
squaring both sides
3²+4²= 2²+(2-k)²
25-4= (k-2)²
21= (k-2)²
±√21= (k-2)
thus, when +ve
k= √21 +2
thus , when -ve
k= -√21 +2
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