Find the value of k if the linear equations x+2y-5=0 and 3x+ky-15=0 have unique solution
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Answer:
x+2y-5=0--------(1)
3x+ky-15=0------(2)
take x=5-2y
using it in equation 2.
3(5-2y) +ky -15=0
15-6y+ky-15=0
-6y+ky=0
-6y= -ky
k=6.
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