Question

Find the value of “ k “ if the pair of equations 2k - y = - 1 and 3x - y = 2 has infinitely many solutions.​

Answer 1

Answer:

k=1

Step-by-step explanation:

3x-y=2

or,y=3x-2

2k-y=-1

substituting y

2k-(3x-2)=-1

or,2k-3x+2=-1

or,2k-3x=-1-2

or,2k-3x=-3

or,2k-(+3)x=-3

Rewriting -

3=(1)(2)+1

or,-1=(1)(2)-3. (Statement 1)

As given,

2k-y=-1

As Statement 1,

-1=(1)(2)-3

or,-1=(2)(1)-3

Hence,k=1