find the value of k if the pair of equations 2x+3y-9 =0 and 4x+ky-18=0 has infinitely many solutions
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Answer:
The required value of k is 6.
Step-by-step explanation:
Given :
The pair of equations 2x + 3y - 9 = 0 and 4x + ky - 18 = 0 has infinitely many solutions
To find :
the value of k
Solution :
Comparing the given two equations with a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0, we get
a₁ = 2 , b₁ = 3 , c₁ = -9
a₂ = 4 , b₂ = k , c₂ = -18
The pair of linear equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 has infinitely many solutions when
Substitute the values,
The value of k is 6
_______________________
Know more :
The pair of linear equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 has
1) no solution when
2) infinite solutions when
3) unique solution when
Anonymous:
Tnqs For Explanation I underatood this concept now
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