find the value of (k) if the pair of linear equations x+3ky=5, 2x+6y=10 have many solutions
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Answered by
1
Answer:
1
Step-by-step explanation:
2x + 6y = 10
2x = 10 - 6y
x = 5 - 3y
x + 3ky =5
5 - 3y +3ky =5
5/y - 3 + 3k = 5/y
3k = 3
k = 1
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