Question

Find the value of k if the pair of linear equs 2x-y = 5
Kx-8y = 7 has a unique solution. (k≠6).​

Answer 1

hope this helps u

coefficient of terms

a₁ = 2  ,b₁ = -1, c₁ = 5

a₂ = k , b₂ = -8 , c₂ = 7

we know that a1/a2 ≠b1/b2

2/k≠-1/-8 -/- cancelled

cross multiplication

2*8≠1*k

16≠k is the answer mate

Answer 2

Answer:

For any k ≠ 16

Step-by-step explanation:

The system of linear equations y = $m_{1}$x + $b_{1}$ and y = $m_{2}$x + $b_{2}$ has only 1 solution, if slopes are different ($m_{1}$ ≠ $m_{2}$)

y = 2x - 5

y = $\frac{k}{8}$x - $\frac{7}{8}$

$\frac{k}{8}$ ≠ 2 ===> k ≠ 16

k ∈ (-∞, 16)∪(16, ∞)