Math, asked by meghashree96, 5 months ago

Find the value of k if the point (2k +3, k-2)
lies on the graph of the equation 3x+7y+8=0.

Answers

Answered by ADITHYANB

2

ANSWER:-3/13

Step-by-step explanation:

SINCE (2k+3,k-2) lies on the graph of the equation 3x+7y+8=0.

it is solution of given eq

substitute (2k+3,k-2) in 3x+7y+8=0

3(2k+3)+7(k-2)+8=0

6k+9+7k-14+8=0

13k+3=0

k=-3/13

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