find the value of k if the point A(8, 1) B(K,- 4) and C (2,-5 )are collinear
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Answer:
Step-by-step explanation:
If the points are collinear .
Therefore, Area of ∆ ABC = 0
1/2{x1(y2-y3) + x2(y3-y1) + x3(y1-y2)} = 0
where, x1= 8, x2=K, x3= 2
And y1=1, y2= -4, y3=-5
Putting all the value in Area of ∆ ABC
1/2{8(-4+5)+K(-5-1)+2(1+4)}= 0
1/2{8(1)+K(-6)+2(5)}= 0
{8-6K+10}= 0
-6K+18= 0
-6K= -18
K= 3
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