find the value of k if the point are A (2,3) B (4,k) C(6,-3) are collinear
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By area formula,
0=1/2[2(k+3)+4(-3-3)+6(3-k)]
0=2k+6+4(-6)+18-6k
0= -4k+24-24
K=-1/4
Area formula is equal to zero since points are collinear
0=1/2[2(k+3)+4(-3-3)+6(3-k)]
0=2k+6+4(-6)+18-6k
0= -4k+24-24
K=-1/4
Area formula is equal to zero since points are collinear
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