Question

find the value of k, if the point (k,0) is equidistant from the point (7,6),(-3,4)​

Answer 1

Explanation:

ANSWER

Distance between two points (x

1

,y

1

) and

(x

2

,y

2

) can be calculated using the

formula

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Given, Distance between the points (2,3);(k,1)= Distance between $$ (2,3) ; (7,k) $$

(k−2)

2

+(1−3)

2

=

(7−2)

2

+(k−3)

2

=>(k−2)

2

+4=25+(k−3)

2

On expanding the squares and simplifying, we get k=13