"find the value of k if the point p(0 ,2) is equidistant from (3, k) and (k, 5)"
In this question usually we take points in form of triangle and solve by distance formula but why can't we take points in straight line and take p as midpoint and solve by mid-point formula?
If we can then please provide solutions for both cases.
Answers
Answered by
2
Using section formula we can also solve this problem....
Let, p(0,2) be the mid- Pt of the line A(3,k) and B(k,5).
So, for x- coordinate,
0= 3+k/2
K= -3
And for y - coordinate,
2=k+5
K= -3
Therefore k=-3.
Hope it helps you....
rjkk12:
That is the real question. Why are the answers different although the conditions are same.
ok so the question does not state that p is the midpoint but how can you assure that p is not the midpoint of the line just by reading the question. I said that p is equidistant so p can be midpoint as well as it can be somewhere else. solving it by midpoint formula is correct according to situations given in the question.
Answered by
0
Heyy mate ❤✌✌❤
Here's your Answer...
⤵️⤵️⤵️⤵️
Using Section Formula,
Let, p(0,2) be the mid point of the line A(3,k) and B(k,5).
So, for x- coordinate,
0= 3+k/2
K= -3
And for y - coordinate,
2=k+5
K= -3
✔✔✔✔
Here's your Answer...
⤵️⤵️⤵️⤵️
Using Section Formula,
Let, p(0,2) be the mid point of the line A(3,k) and B(k,5).
So, for x- coordinate,
0= 3+k/2
K= -3
And for y - coordinate,
2=k+5
K= -3
✔✔✔✔
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