Question

Find the value of k, if the point P (-1,2) is equidistant from the points A (5, k) and B (k, 7).

Answer 1

Answer:

value of k = 1 or 5

Step-by-step explanation:

Given the point P(k-1,2) is equidistant from the points A(3,k) and B(k,5)

A( x1 y1 ) and A ( x1 y1 ) is root (x2-x1)2 + (y2-y1)2

here, ap = bp

ap2 = bp2

[(k-1) -3]2 + (2-k)2 = k-1-k2+ 2-(5)2

k2-6k+5=0

by splitting

k(k-1)-5 (k-1)

(k-1) (k-5) = 0

k=1 or 5

Answer 2

Answer:

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