Question

find the value of k,if the point p (2,4)is equidistant from the points (5,k) k,7).

Answer 1

The point P(k – 1, 2) is equidistant from the points A(3, k) and B(k, 5) ⇒ PA = PB PA = √[( 3 - k + 1)2 + (k - 2)2] = √[(16 + k2 - 8k) + (k2 - 4k + 4)] = √(2k2 - 12k + 20) PB ...