find the value of K , if the points (7,2),(5,1) & (3,k) are collinear
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Answer:
0
Step-by-step explanation:
Given,A(7,2) (x1,y1)
B(5,1). (x2,y2)
C(3,k) (x3,y3)are collinear.
Then,area of triangle=0
area of ∆le=|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
0 =|7(1-k)+5(k-2)+3(2-1)|
0 =|7-7k+5k-10+6-3|
0 =|7-2k-7|
0 =|-2k|
therefore, 0 =k
HOPE U UNDERSTOOD
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