Question

Find the value of K if the points A(2,3),B(4,k) and C(6,-5) collinear

Answer 1

Step-by-step explanation:

A(2,3)[ x1,y1]

B(4,k)[ x2, y2]

C(6, -5)[ x3, y3]

GN.that ar(∆ABC)= 0{collinear}

ar(∆ABC)= 1/2[x1(y2-y3)+ x2(y3-y1) + x3(y1-y2)]

0= 3(k+5)+4(-5-3)+6(3-k)

0= 3k+15+4(-8)+18k-6k

0= 3k-6k+18k+15-32

17= 15k

K= 15/17