Question

find the value of K if the points A(2,3) B(4,K) C(6,-3) are collinear.

Answer 1

Hey there!

THE SOLUTION IS IN THE ABOVE PIC. ↑↑

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Answer 2

The formula is 1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0

                       = 1/2(2(k+3) + 4(-3-3)+6(3-k)=0

                       = 2k + 6 - 24 + 18 - 6k = 0

                       = 24-24-4k = 0

                      = -4k = 0

                      k = 0.