find the value of k if the points a(8 1) b(3 -4) and c(2 k) are collinear
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Answer:
A(8,1) B(3,-4) C(2,k)
Since points are collinear , area will be 0
area = 1/2 [x1(y2-y3) + x2 (y3-y1) + x3(y1-y2) ]
0=1/2 [8(-4-k) + 3(k-1) + 2(1+4) ]
0 × 2 = -32-8k + 3k -3 + 10
0= -5k-25
5k = -25
k = -25/5
∴k = -5
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2
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hope it helps ✌️..........
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