find the value of k if the points (k,3), ,(6-2) and (-3,4) are collinear
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Step-by-step explanation:
apply the formula of triangle
area of triangle=0
by substituting you get answer
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Given:
- Points (k,3) , (6, -2) , (-3,4) are collinear.
To find:
- Value of k?
Solution:
Here,
- x₁ = k , y₁ = 3
- x₂ = 6 , y₂ = - 2
- x₃ = - 3 , y₃ = 4
Given that,
- Points are Collinear.
Collinear points:
- Collinear points are the points that lie on the same line. If two or more than two points lie on a line close to or far from each other, then they are said to be collinear.
Therefore,
⇒ x₁ (y₂ - y₃) + x₂ (y₃ - y₁) + x₃ (y₁ - y₂) = 0
⇒ k(- 2 - 4) + 6(4 - 3) + 3(3 + 2) = 0
⇒ k(- 6) + 6(1) + (-3) × 5 = 0
⇒ - 6k + 6 - 15 = 0
⇒- 6k - 9 = 0
⇒ - 6k = 9
⇒ k = 9/6
⇒ k = 3/2
Hence, Value of k is 3/2.
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