Question

Find the value of k' if the points (K, 3), (6,-2)
and (-3,4) are collinear​

Answer 1

Answer:

(k,3),(6,-2),(-3,4) are

collinear

here x

1

=k,y

1

=3

x

2

=6,y

2

=−2

x

3

=−3,y

3

=4

So, as given that the points are collinear, then,

x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)=0

k(−2−4)+6(4−3)+3(3+2)=0

k(−6)+6(1)+(−3)×5=0

−6k+6−15=0

−6k−9=0

k=

6

9

=

2

3

Answer 2

Step-by-step explanation:

My handwriting is not good but I hope it will be help full for you