Question

Find the value of k if the polynomial p(x) = 3xcube+kxsquare +5x - 16 is divided by (x-2) leaves a remainder -8. )

Answer 1

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$x-2=0$

$x=2$

Now, put the value of x in given p(x).

$p(2)=3(2)^3+k(2)^2+5(2)-16=-8$

$24+4k+10-16=-8$

$18+4k=-8$

$4k=-18$

$k=\frac{-18}{4 }$

$k=\frac{-9}{2}$

Thank You!

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