Question

Find the value of k if the polynomial p(x) = kx^3 + 9x^2+4x-10 is divided by (x-2) leaves a remainder -22

Answer 1

Hello Dear!!!

Here's your answer....

Given that,

 p(x) = k(x)^3 + 9(x)^2+4x-10

g(x) = x-2

zero of (x-2) is

x-2 = 0

x=2

substitute the value of x in p(x)

 p(x) = k(x)^3 + 9(x)^2+4x-10

k(2)^3 + 9(2)^2 + 4(2) - 10 = -22

8k + 9(4) + 8 -10 = -22

8k + 36+8-10 = -22

8k +34 = -22

8k = -22 - 34

8k = -56

k= -56/8

k = -7

The value of k is -7

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HOPE THIS HELPS YOU.....