Find the value of k if the polynomial x+2x-kx²+x-1 exactly divisible by (x+2)
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k =7/4
zero of the polynomial x=-2
p(x)= x+2x+x-kx²-1=0
4x -kx² -1 =0
-kx²+4x-1 =0 ( since quadratic equation
start with x² and it should be
+ve)
-(kx²-4x+1) =0
kx²-4x+1=0
p(-2)=k× (-2)^2 -4×2+1=0
remaining step in the photo
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